Question

divide 84 into two parts such that 1/4 of one part is equal to 1/3 of the other part ?

Answer 1

Let the one part be x
The second part be y
X + y = 84........(1)
1/4 x = 1/3 y
1/4 x -1/3 y = 0
Multiple through out by 12
12×1/4 x- 12×1/3 y = 0
3x - 4y = 0........(2)
Multiply 1 by3
3x + 3y = 84..........(3)
Solve 3 and 4 simultaneously
Y = 12
X = 16

Answer 2

Answer:

Step-by-step explanation: