divide a rope of length 560 cm into two parts such that twice the length of the smaller part is equal to 1/3 of the larger part then find the length of the larger part
Answers
Answered by
2
Answer: 480
Step-by-step explanation:
Let ,
Smaller part-time x
Then,Larger part- 560-x
Given,
2x=1/3(560-x)
Solving it we will get x=80
Then Larger part would be= 560-80
= 480
Dayitha:
Thanks
Answered by
3
Let the length of smaller part be x cm and the length of longer part will be 560-x
According to the question
2x=1/3(560-x)
6x=560-x
6x+x=560
7x=560
x=80
Length of smaller part = 80cm
Length of Longer part=560-x=480cm
According to the question
2x=1/3(560-x)
6x=560-x
6x+x=560
7x=560
x=80
Length of smaller part = 80cm
Length of Longer part=560-x=480cm
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