Question

Divide p by 60,150 and 285 is the largest number given for each remainder because p is the sum of the digits?​

Answer 1

Answer:

Aptitude :: Problems on H.C.F and L.C.M - Discussion

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: [A]. = H.C.F. of 3360, 2240 and 5600 = 1120.

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Answer 2

Answer:

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is: [A]. = H.C.F. of 3360, 2240 and 5600 = 1120.