Root 2^x= root 3^x find x
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Answer:
V6,-(V6/3) are two roots of given Quadratic
equation.
Explanation:
Given quadratic equation:
V3x2-2/2x-23-0
Splitting the middle term, we get
=> V3x2-372x+v2x-2v3=0
=> 3x2-3x3x/2x+/2x-2x/2x/3-0
=> 13x(x-16)x+ 2(x-V6)=0
(x-v6V3xtv2)-0
= x-v6-0 Or v3x+v2-0
=>x V6 Or x = (-2) //3
xv6 Or x = -(V6)/3
Therefore,
V6, -(V6/3) are two roots of given Quadratic
equation.
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