Question

divide p x by g x where X is equals to X + 3 x square - 1 and X is equals to 1 + x​

Answer 1

$p(x) = x + 3 {x}^{2} - 1 \\ g(x) = 1 + x \\ the \: zero \: of \: the \: polynomial \: of \: 1 + x \: is \: 0 \\ \: \: \: \: \: \: \: 1 + x = 0 \\ \: \: \: \: \: \: \: \: x = - 1 \\ p( - 1) = - 1 + { - 1}^{3} - 1 \\ \: \: \: \: \: \: = - 1 - 1 - 1 \\ \: \: \: \: \: \: \: \: \: = - 3$

Answer 2

I think that brainly moderators do not like my answer because they said that your answer is incorrect so I had taken a screenshot of it.