Question

divide p(x)=x³-7x²+11x-10 by g(x)=x-3 find reminder.​

Answer 1

$hey \: mate \: here \: is \: the \: answer$

Zero of g( x ) = x - 3 is x = 3 right

So by remainder theorem if r is remainder so

r = p(3) = (3)^3 - 7(3)^2 + 11(3) - 10

= 27 - 7(9) + 33 - 10

= 27 - 63 + 33 - 10 = - 13

Hope it helps you

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