Question

Divide R6840 between x y and x in such way that x has twice as much as y, who has half as z

Answer 1

Answer:

Make equation according each condition

$x + y + z = 6840 \\ x = 2y \\ x = \frac{z}{2} \: \: or \: \: z = 2x$

Substitute values

$x + \frac{x}{2} + 2x = 6840 \\ x = \frac{6840 \times 2}{7} = 1954.28 \\ y = 977.14 \\ z = 3908.56$

Answer 2

Answer:

Let x's share be Rs a.

∴ y's share=Rs a/2;

∴ z's share=Rs a;

[Read the question properly to understand the above steps]

∴ According to the problem,

a+(a/2)+a=6840

[Now..simply solve....]

a=2736 ;a/2=1368.

Thus, x and z both get Rs 2736 each; y gets Rs 1368. (Ans)