Question

divide the following (x³-6x²+12x-5) by (x+3) ​

Answer 1

Answer:

One way to solve this problem is to perform polynomial long division. We write the polynomial and its divisor down in long division form and work through the normal steps of long division. Then we guess our first term in the quotient, which should subtract from the first term in the dividend shown in red below:

x2−4x+4x−2¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯)x3−6x2+12x−8−x3+2x2¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯ −4x2+12x 4x2−8x ¯¯¯¯¯¯¯¯¯¯¯¯¯¯ 4x−8 −4x+8 ¯¯¯¯¯¯¯¯¯¯¯¯ 0

We then repeat this step for the next powers of x shown in blue and green. We end up with a zero remainder.

x3−6x2+12x−8

Step-by-step explanation:

I hope it's help you

Answer 2

Answer:

Step-by-step explanation:

Let p (x) = x³-6x²+12x-5 and g (x)=x +3

If x+3 is a factor of p (x) ,then x+3=0⇒x= -3.

Now substituting " x = -3 " in p (x) ,we get

p ( -3)= (-3)³ - 6 (-3)² + 12 (-3) -5

= -27 - 6 (9) + (-36) - 5

= - 27 - 54 - 36 - 5 (∵ - × + = - , + × - = - )

= - 122 is the answer. ( ∵ adding -27-54-36-5 = - 122)