Question

Divide the polynomial (23y^2+9+20y^3-13y) by (2+5y^2-3y)​

Answer 1

Answer:

quotient = 4y +7 & remainder = 2y-5

Answer 2

Answer: See image below

Step-by-step explanation:

(23y^2+9+20y^3-13y) ÷ (2+5y^2-3y)

Writing in order,

(20y^3 + 23y^2- 13y + 9) ÷ (5y^2 -3y+2)

See below for division