divide the sum of -2/9 and 1/3 by the reciprocal of the difference of 1/4 and -3/4.
anyone please answer fast
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Answered by
1
Sum = -2/9 + 1/3
→ -2+3/9 { We made the denominator same }
→ +1/9
Difference = 1/4 - (-3/4)
→ 1+3/4
→ 4/4
→ 1/1
→ Reciprocal is same
Division → 1/9 * 1/1
→ 1/9
Hope it helps •_•
→ -2+3/9 { We made the denominator same }
→ +1/9
Difference = 1/4 - (-3/4)
→ 1+3/4
→ 4/4
→ 1/1
→ Reciprocal is same
Division → 1/9 * 1/1
→ 1/9
Hope it helps •_•
amalaammu19:
thank u so much
Mark this as brainliest
Answered by
2
(-2/9+1/3)÷(-3/4-1/4)
= (-2+3/9)÷(-3-1/4)
= 1/9÷(-4/4)
Reciprocal of the difference of 1/4 and -3/4 is 4/-4
= 1/9÷4/-4
= 1/9×(-4/4)
= -4/36= -1/9.
= (-2+3/9)÷(-3-1/4)
= 1/9÷(-4/4)
Reciprocal of the difference of 1/4 and -3/4 is 4/-4
= 1/9÷4/-4
= 1/9×(-4/4)
= -4/36= -1/9.
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