Find the no. of sides of a polygon, the sum of whose interior angle is 720 o .
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Using the formula : (n-2)×180° = the sum of interior angles .
When the sum of interior angles is 720° ,therefore,
(n-2)×180=720
n-2=720÷180
n-2 = 4
n = 4 + 2
n=6.
∴ the polygon has six sides.
When the sum of interior angles is 720° ,therefore,
(n-2)×180=720
n-2=720÷180
n-2 = 4
n = 4 + 2
n=6.
∴ the polygon has six sides.
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