dividing X3 -a x 2 + 6 x - 1 by ( x- a)
Answers
Answered by
2
Answer:
We have x
3
+1=(x+1)(x
2
−x+1).
Now,
(x+1)
x
3
+1
=
x+1
(x+1)(x
2
−x+1)
=(x
2
−x+1).
So when x
3
+1 is divided by (x+1) then the quotient be x
2
−x+1 and the remainder will be 0 [ Since x
3
+1 is perfectly divisible by (x+1)]..
Step-by-step explanation:
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Answered by
0
Answer:
We have x
3
+1=(x+1)(x
2
−x+1).
Now,
(x+1)
x
3
+1
=
x+1
(x+1)(x
2
−x+1)
=(x
2
−x+1).
So when x
3
+1 is divided by (x+1) then the quotient be x
2
−x+1 and the remainder will be 0 [ Since x
3
+1 is perfectly divisible by (x+1)]..
Step-by-step explanation:
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