Math, asked by 4254darshtripathi10b, 3 months ago

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Answered by Atαrαh
4

Solution :-

As per the given data ,

  • Image distance (u) = - 18 cm ( distances are always measured from the optical center of the lens )
  • focal length (f) = 20 cm

By using lens formula ,

➜  1 / f = 1 / v - 1 / u

➜ 1 / v = 1 / f + 1 / u

Now let's substitute the given values in the above equation ,

➜ 1 / v = 1 / 20 - 1 / 18

➜ 1 / v = 9 - 10 / 180

➜ 1 / v = - 1 / 180

➜ v = - 180 cm

The image is formed at a distance of 180 cm on the same side as that of the object

Magnification

➜ m = v / u

➜ m = - 180 / - 18

➜ m = 10

The image formed is erect , virtual and magnified .

Answered by jiya2747
6

Answer:

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