Question

Do the formation of XeF4 and XeF6 in sp^3d hybridization​

Answer 1

Answer:

Hybridisation is given as

Totalnumberofbondpairs

+

Totalnumberoflonepairs

XeF

2

2 + 3 = 5

SP

3

d

XeF

4

4 + 2 = 6

SP

3

d

2

XeF

6

6 + 1 = 7

SP

3

d

3

So the answer is

sp

3

2

sp

3

3

sp 3

Explanation:

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