Question

Do the points (3, 2), (–2, –3) and (2, 3) form a triangle? If so, name the type of triangle formed.. ​

Answer 1

❤Holå mate❤

✏ANSWER✍

✒ Solution :

Let us apply the distance formula to find the distances PQ, QR and PR, where P(3, 2), Q(–2, –3) and R(2, 3) are the given points. We have

PQ = √(3+2)² + (2+3)² = √5²+5² = √50 = 7.0 7(Approx).

QR = √(-2-2)² + (-3-3)² = √(-4)² + (-6)² = √52 = 7.21(Approx).

PR = √(3-2)² + (2-3)² = √1² + (-1)² = √2 = 1.41 (Approx).

Since the sum of any two of these distances is greater than the third distance, therefore, the points P, Q and R form a triangle.

Also, PQ2 + PR2 = QR2, by the converse of Pythagoras theorem, we have.

∠ P = 90°.

Therefore, PQR is a right triangle..

✌Hope it's help you✌

Answer 2

Answer is in the attachment.