Physics, asked by Shivam901, 1 year ago

do...the question geostationary.....

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Answered by siddhartharao77
1

Given, Mass of earth M = 6 * 10^24 kg


Given, Mass of satellite, m = 200 kg


Given, Radius Re = 6.4 * 10^6 m


W.K.T gravitational constant, G = 6.67 * 10^-11


Given, Height of the satellite, h = 400 km = 0.4 * 10^6


Total energy of the satellite at height h = 1/2 mv^2  + (-GMem/Re + h)  ---- (1)


Orbital velocity of the satellite v = root GMe/Re+h  ----- (2)



Substitute (2) in (1), we get


h = 1/2 m (GMe/Re+h) - GMe/Re+h


    = -1/2(GMe/Re+h)


Energy required to expand the satellite = 1/2(GMe/Re+h)


                = 1/2 * 6.67 * 10^-11 * 6 * 10^24*200/(6.4 * 10^6 + 0.4 * 10^6)


                = 5.9 * 10^9 J.


Hope this helps!  


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