do this with clear process in paper and send
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Step-by-step explanation:
sinA+sin(240+A)+sin(120+A)
=sinA+2sin(240+A+120+A)/2 ×cos(240+A-120-A)/2
=sinA+2sin(360+2A)/2×cos120/2
=sinA+2sin(180+A)×cos60
=sinA+2(-sinA)×1/2
=sinA-sinA
=0
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Hope this will help you...
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