Question

Don't spam
solve this.
gud night guys.

​

Answer 1

Solution :-

we have

$\int \sf \frac{2x - 1}{2x + 3} \: dx \: = x - log {(2x + 3)}^{2} + c$

Explanation :-

Taking left hand side

$\red{ \leadsto } \green{\: \int} \orange{ \sf \frac{2x - 1}{2x + 3} \: dx \: } \\ \\ \leadsto \sf \int \: \frac{2x + 3 - 4}{2x + 3} dx \\ \\ \leadsto \sf \int \bigg( \frac{2x + 3}{2x + 3} - \frac{4}{2x + 3} \bigg) \: dx \\ \\ \leadsto \sf \int \:1 \: dx \: -4 \int \: \frac{1}{2x + 3} dx \\ \\ \leadsto \sf x - \frac{4}{2} log(2x + 3) + c \\ \\ \leadsto \sf x \: - log{(2x + 3)}^{2} + c \:$

Hence verified

Brainlist ✌️

Answer 2

Answer:

see the attachment.

Step-by-step explanation: