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In triangle ABE and DCE
AB=DC(OPP. SIDES OF SQUARE)
AE=DE(E IS MIDPT.OF AD)
Angle BAE= angle CDE(ANGLES OF SQUARE ARE EQUAL)
TRIANGLE ABE IS CONGRUENT TO TRIANGLE DCE BY SAS CONGRUENCY
BE=CE(CPCT)
AS TWO SIDES OF A TRIANGLE ARE EQUAL THE TRIANGLE BED IS AN ISOSCELES TRIANGLE
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