Draw a circle and draw at least 5 chords in it. Make sure at least one of passes through the centre. Name them and fill the table
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Answer:
P be the given point inside a circle with centre O.
Draw the chord AB which is perpendicular to the diameter XY through P.
Let CD be any other chord through P. Draw ON perpendicular to CD from O.
Then, △ONP is a right triangle.
Therefore, its hypotenuse OP is larger than ON.
We know that the chord nearer to the centre is larger than the chord which is farther from the centre.
Therefore, CD>AB
In other words, AB is the smallest of all chords passing through P.
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