Question

Draw a rough sketch of a regular hexagon connecting any three of its Vertices,draw a triangle.Indentify the type of the triangle You have drawn.​

Answer 1

Question

$\large\purple\leadsto$Draw a rough sketch of a regular hexagon connecting any three of its Vertices,draw a triangle.Indentify the type of the triangle You have drawn.

Answer

a).$\large\green\leadsto$ In a regular hexagon all sides are equal.

$\large\green\leadsto$By connecting vertices A,C or F,D or B,F,etc.we form triangles where the two sides of the hexagon becomes two sides of the triangle which are equal,making them isosceles triangle.

b).$\large\green\leadsto$ By conneting vertices A, C and F,we form a right-angled triangle.CAF where ∠CAF = 90°

$\large\green\leadsto$Similarly,by joining vertices D,A and F we form a right-angled triangle DFA where ∠DFA = 90°

c).$\large\green\leadsto$ By joining the vertices B,F and D,we form an equilateral triangle(all the sides are equal)

$\large\green\leadsto$Many such triangles can be formed by jointing any three vertices of a regular hexagon.

Answer 2

$\large{ \textsf{ \textbf{ \red{Answer}}}}$

a) $\large\purple\to$ In a regular hexagon all sides are equal.

$\large\purple\to$ By connecting vertices A, C or F, D or B, F, etc. we form triangles where the two sides of the hexagon becomes two sides of the triangle which are equal, making them isosceles triangle.

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b) $\large\purple\to$ By conneting vertices A, C and F,we form a right-angled triangle. CAF where ∠CAF = 90°.

$\large\purple\to$Similarly, by joining vertices D, A and F we form a right-angled triangle DFA where ∠DFA = 90°.

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c) $\large\purple\to$ By joining the vertices B, F and D, we form an equilateral triangle(all the sides are equal).

$\large\purple\to$ Many such triangles can be formed by jointing any three vertices of a regular hexagon.

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$\orange\implies$ Rough sketches refers to attachments.

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