Draw a schematic diagram of a circuit consisting of a battery of three cells of 2 V each, a 4
Ω resistor, 8 Ω resistor, and a 12 Ω resistor, and a plug key, all connected in series. [5]
(a)Calculate the current flowing through 4Ω resistor.
(b)Calculate the potential difference across 12Ω resistor.
(c)Calculate the equivalent resistance of the circuit.
Answers
Answer:
a) I=volt/ampere
I=2×3/4=1.5A
b)V=IR
V=1.5×12=18V
c)R=R1+R2+R3
R=4+8+12=24ohms
Answer:
Refer to the attachment for diagram consisting of:
- A battery of three cells 2 V each
- A 4Ω resistor, a 8Ω resistor, a 12Ω resistor
- A plug key, all connected in series.
Solutions for (a), (b) and (c)
To find:-
- Current flowing through 4Ω resistor
- The Potential difference across 12Ω resistor
- The equivalent resistance of the circuit
Solution:-
There are three cells in the battery, each of 2 V so,
→ Potential difference of battery, V = 2 V + 2 V + 2 V = 6 V
Calculating the equivalent resistance of the series circuit
→ R(eq) = 4Ω + 8Ω + 12Ω = 24 Ω
Using the expression for ohm's law
→ V = I R
[ where V is the potential difference, I is current and R is resistance ]
Calculating the current flowing through the whole circuit
→ I = V / R
→ I = 6 / 24
→ I = 1 / 4 = 0.25 A
[In a series combination, all the connected resistors have the same current flowing through them that is equal to the current flowing in the whole circuit.]
Therefore,
- Current flowing through the 4Ω resistor will be 0.25 A
- and, Equivalent resistance of the circuit will be 24 Ω
Now, we need to find the potential difference across 12Ω resistor
[Because In a series combination, all the connected resistors have the same current flowing through them that is equal to the current flowing in the whole circuit.]
so the current through 12Ω resistor will be 0.25 A
Hence, Using Expression for ohm's law
calculating the potential difference (V') through R' = 12Ω resistor
→ V' = I R'
→ V' = 0.25 × 12
→ V' = 3 V
Therefore,
- The potential difference through the 12Ω resistor will be 3 V.
Extra shots:-
- Combined resistance of any number of resistors connected in series is equal to the sum of the individual resistances.
- Sum of potential difference across all the resistances is equal to the voltage of the battery in series, but different potential differences across different resistors.
- The number of resistances in series has the same current flowing through each resistor that is equal to the current flowing in the whole circuit.