Question

draw a triangle ABC in which BC=5.2cm ,angle B =60degree and angle A=100degree​

Answer 1

Given data:-

a triangle with side BC=5.2cm, angle B=$60^{0}$ and angle A=$100^{0}$

To Construct:-

a triangle ABC

Explanation:-

1. Firstly, draw a horizontal line segment of side BC=5.2cm.
2. With the help of protactor, draw a line from point B having angle $60^{0}$ from the horizontal.
3. Since, total sum of angles in a triangle is $180^{0}$.Therefore, angle C=180-(60+100)=$20^{0}$    
4. Now, with the help of protactor, draw a line from point C having angle $20^{0}$ from horizontal in counter-clockwise direction.
5. The line originated from point B & C meets at a common point A and triangle ABC is completed.