Question

Draw the graph of d polynomial p(x) =x^2-5x+6
P(x) = x^2-3x+2
P(x)=x^2+4x+3
And find the zeros from the graph

Answer 1

Heya !!!

This is your answer.

Given :-
p (x) = x² - 3x + 2

We have to search for two numbers a and b such that A+B = -3 and AB = 2.

By looking at prime factors of 2...
2 = 1×2

We get a and b as -1 and -2.

Therefore.....
x² - 3x + 2 = 0
x² - 2x - x + 2 = 0.
x (x-2) - 1 ( x-2) = 0.
(x -1)(x -2) =0.

Comparing with 0....
x - 1 = 0 or x -2 = 0.
x = 1 or x = 2.
Hence the two zeroes of the given polynomial are 1 and 2.


Next.....
p (x)=x²+4x+3
We have to search for two numbers a and b such that A+B = 4 and AB = 3.

By looking at prime factors of 2...
3 = 1×3

We get a and b as 1 and 3.

Therefore.....
x² + 4x + 3 = 0
x² + 3x + x + 3 = 0.
x ( x +3) +1 (x+3) = 0.
(x + 1) (x + 3) = 0

Comparing with 0,
x + 1 = 0 or x + 3 = 0.
x = -1 or x = -3.

Hence, the two zeroes of the equation are -1 and -3.

Hope it helps

Answer 2

Draw the graph of d polynomial p(x) =x^2-5x+6

P(x) = x^2-3x+2

P(x)=x^2+4x+3

And find the zeros from the graph