Draw the graph of the linear equation F= 9/5 (K-273) + 32. No fake answers or will be reported.
Answers
SOLUTION
TO DETERMINE
Draw the graph of the linear equation
EVALUATION
Here the given equation is
We simplify it as below
Graph : Graph is referred to the attachment
In the graph we have taken F along horizontal direction and K along vertical direction
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Answer:
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Step-by-step explanation:
Draw the graph of the linear equation
\displaystyle \sf{F = \frac{9}{5}( K - 273) + 32}F=59(K−273)+32
EVALUATION
Here the given equation is
\displaystyle \sf{F = \frac{9}{5}( K - 273) + 32}F=59(K−273)+32
We simplify it as below
\displaystyle \sf{F = \frac{9}{5}( K - 273) + 32}F=59(K−273)+32
\displaystyle \sf{ \implies \: 5F = 9( K - 273) + 160}⟹5F=9(K−273)+160
\displaystyle \sf{ \implies \: 5F = 9K - \: 2457 + 160}⟹5F=9K−2457+160
\displaystyle \sf{ \implies \: 5F - 9K = - 2297}⟹5F−9K=−2297
Graph : Graph is referred to the attachment
In the graph we have taken F along horizontal direction and K along vertical direction
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