Draw the graph of the polynomial p(x)=x^-4x-5 and find its zeroes.
Answers
Answered by
32
x^2-4x-5 = 0
x^2+1x-5x-5 = 0
x(x+1) -5(x+1) = 0
(x-5)(x+1) = 0
x= +5 & -1
The graph can be drawn by plotting the coordinates (5,0) & (-1,0) on the X-Axis
x^2+1x-5x-5 = 0
x(x+1) -5(x+1) = 0
(x-5)(x+1) = 0
x= +5 & -1
The graph can be drawn by plotting the coordinates (5,0) & (-1,0) on the X-Axis
Answered by
22
p(x) = x^2 - 4x - 5
= x^2 - 5x + x -5
= x ( x - 5) + 1(x - 5)
= (x + 1)( x - 5)
So we have got 2 zeroes..
x + 1 = 0. and x - 5 = 0
x = -1. and. x = 5
Graph can be drawn by taking out the x values and plotting it accordingly
= x^2 - 5x + x -5
= x ( x - 5) + 1(x - 5)
= (x + 1)( x - 5)
So we have got 2 zeroes..
x + 1 = 0. and x - 5 = 0
x = -1. and. x = 5
Graph can be drawn by taking out the x values and plotting it accordingly
Similar questions