Draw the graph of x+2y-7=0 and 2x-y-4=0 Shade the area bounded by there line and y-axis.
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Answered by
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hope it helps u....
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Mark my answer as brainliest if u like
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kevinmillet02:
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Answered by
78
ΔGiven,
Equations:-
x + 2y -7 = 0 ----------------(i)
&,
2x - y - 4 = 0 --------------(ii)
By seeing the equations we come to know that these are linear equations.
because they have power as 1 ;.(x ¹+ 2y¹ -7 = 0 )
Take eqn(i)
x + 2y -7 = 0
⇒ 2y = 7 - x
⇒ y = (7 - x)/2
To plot a line on graph we need atleast two points.
Substitute any random values for or y and get the points,
if x = 0 ; y = 7/2 = 3.5
point: A(0, 3.5)
if y = 0 ; x = 7
point: B(7, 0)
plot the points A(0, 3.5) & B(7, 0) on graph and join the points AB.
So a line is formed AB. that is the graph of the equation(i).
(2). Take eqn(ii)
2x - y - 4 = 0
⇒ y = 2x - 4
if y = 0; x = 2
Point: P(2, 0)
if x = 0; y = -4
point: Q(-4, 0)
Line PQ is formed by joining the points P and Q.
See the graph here in attachement.
Equations:-
x + 2y -7 = 0 ----------------(i)
&,
2x - y - 4 = 0 --------------(ii)
By seeing the equations we come to know that these are linear equations.
because they have power as 1 ;.(x ¹+ 2y¹ -7 = 0 )
Take eqn(i)
x + 2y -7 = 0
⇒ 2y = 7 - x
⇒ y = (7 - x)/2
To plot a line on graph we need atleast two points.
Substitute any random values for or y and get the points,
if x = 0 ; y = 7/2 = 3.5
point: A(0, 3.5)
if y = 0 ; x = 7
point: B(7, 0)
plot the points A(0, 3.5) & B(7, 0) on graph and join the points AB.
So a line is formed AB. that is the graph of the equation(i).
(2). Take eqn(ii)
2x - y - 4 = 0
⇒ y = 2x - 4
if y = 0; x = 2
Point: P(2, 0)
if x = 0; y = -4
point: Q(-4, 0)
Line PQ is formed by joining the points P and Q.
See the graph here in attachement.
Attachments:
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