Question

Draw the structure of (a) 2-methylbut-1-ene , (b) 3-chlorobutanoic acid , (c) butanal

Answer 1

Answer :

Refer to the attachment.

Step-by-step explanation :

a). 2-methylbut-1-ene

Formula - $C_{4}H_{10}$

In this, the methyl group is attached to second C-atom and the double bond is present between the first and second C-atom

b). 3-chlorobutanoic acid

Formula - $C_{4}H_{7}ClO_{2}$

In this, chlorine is atrached to third C-atom and the carboxylic acid group is on the first C-atom.

c). Butanal

Formula - $C_{4}H_{8}O$

In this, aldehyde group would be present on the first C-atom and the number of carbons in principal chain is 4 carbon.

Answer 2

Refer to the attachment ..