Question

draw triangle ABC such that AB= 8 cm BC=
6 cm and angle ABC is equal to 90.draw a circle passing through B,D,A show that line is tangent of the circle​

Answer 1

First we draw a rough sketch of Triangle ABC

Now it is given circle is drawn through points B, C, D

Let's draw a circle through points B, C, D

Now we see that angle BDC = 90°

We know that angle in a semicircle is a right angle, So BC must be the diameter

Now

1). We construct triangle ABC

2). No need to mark point D

3). We find centre of circle - which will be mid point of BC

4). So we draw perpendicular bisector of BC and find centre of circle

5). Through centre of circle, we draw circle.

6). Then we draw tangents from point A to the circle.

STEPS TO DRAW TRIANGLE ABC

Draw BC of side 8 cm

Draw angle B = 90°

Taking B as centre, 6 cm as radius, we draw an arc

Let the point where arc intersects the ray be point A

Join AC

STEPS TO DRAW CIRCLE AND TANGENTS

Draw perpendicular bisector of line BC

Let the line intersect BC at point E

Now E is the midpoint of BC

Taking E as the centre, and BE as radius, draw a circle

We need to construct tangents from point A to the circle

Join point A to the centre of circle E

Make perpendicular bisector of AE

Let M be the midpoint of AE

Taking M as the centre and MA as the radius, draw a circle

Let blue circle intersect the other circle at B and Q

Join AQ

Thus AB and AQ are the required tangents