Draw velocoty-time graph of a body which
accelerates uniformly
and attains a
speed of 10m/s
in 5 sec and
then continue to move
for
another 10 seconds
with
uniform speed of 10 m/s
finally comes to rest in 5 seconds.
Answers
Answered by
1
Answer:
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Step-by-step explanation:
The total distance travelled is
=
625
m
Explanation:
The initial velocity is
u
=
0
m
s
−
1
The acceleration is
a
=
10
m
s
−
2
The time is
t
=
5
s
Apply the equation of motion
v
=
u
+
a
t
The velocity is
v
=
0
+
10
⋅
5
=
50
m
s
−
1
The distance travelled in the first
5
s
is
s
=
u
t
+
1
2
a
t
2
=
0
⋅
5
+
1
2
⋅
10
⋅
5
2
=
125
m
The distance travelled in the following
10
s
is
s
1
=
v
t
1
=
50
⋅
10
=
500
m
The total distance travelled is
d
=
s
+
s
1
=
125
+
500
=
625
m
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