dude I am a two digit number whose sum is 9 if 27 added to make my value will reverse find my value
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I think 63 or 36 or 80 or08
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Let’s say x is the unit digit and y is the tenth digit.
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
Now,
y+x=9
y+6=9
y=3
Hence,
The original no. is 36
hope it helps!!
y+x = 9 -> y=9-x
10x+y = 10y+x+27
10x+9-x = 10(9-x)+x+27
10x+9-x = 90–10x+x+27
18x = 108
x = 6
Now,
y+x=9
y+6=9
y=3
Hence,
The original no. is 36
hope it helps!!
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