due to some health problems of a passenger an aeroplane started late by 1 hour from the starting point after treatment of aj passenger by pilot in the pilot decided to increase the speed of the aeroplane 100 km per hour its usual speed to cover a journey of 1200 km in time. 1.find the usual speed of the aeroplane . 1what value of the are represented here ? (maths solutions)
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Let its original speed be x
Original time taken (OT) = 1200/x
New time (NT) = 1200/x+100
According to the question
OT - NT = 1
1200 / x - 1200/x+100 = 1
1200(x+100) - 1200x / x2 + 100x = 1
1200x+120000 - 1200x / x2 + 100x = 1
120000 = x2 + 100x
x2 + 100x - 120000 = 0
x2 + 400x - 300x - 120000 = 0
x (x + 400 ) -300 (x + 400) = 0
(x +400 ) (x-300) = 0
X = -400
X = 300
Speed cant be negative
Therefore
X = 300km/hr
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