Question

During an experiment, a signal from a spaceship reached the ground station in five minutes. What was the distance of the spaceship from the ground station? The signal travels at the speed of light, that is 3X 10^8 ms^-1

Answer 1

Answer:

Given:

The taken for signal to reach ground = 5 min.

Speed of signal = 3 × 10^8 m/s

To find:

Distance of spaceship from ground

Concept:

Distance is a scalar Quantity representing the total path length travelled by any object. It only has magnitude . Distance will always be positive.

Calculation:

Distance is given as the product of speed and time.

$d = speed \times time$

$= > d = (3 \times {10}^{8} ) \times (5 \times 60)$

$= > d = (3 \times {10}^{8} ) \times (300)$

$= > d = 9 \times {10}^{10} \: m$

So distance is :

$\boxed{ \red{ \huge{ \bold{d = 9 \times {10}^{10} \: m}}}}$

Additional information on Displacement:

• Displacement is the shortest length between starting point and stopping point.
• It is a vector
• It can be negative, zero or positive.

Answer 2

Given

During an experiment with spaceship

Time=5min=300s

Speed of signal=3x$10^8ms^-1$

To find

Distance of Spaceship From Ground

Solution

Let the distance between spaceship and ground station be S'

${\boxed{\boxed{S=Vt}}}$

Then

S=vt

where

v=Speed of signal

t=time taken

$\because$=3x$10^8ms^-1$ × 300

S=9 x $10^{10}$

${\boxed{\boxed{S=</u><u>10^</u><u>{</u><u>1</u><u>0</u><u>}</u><u>m</u><u>}}}$

Hence,the Distance of Spaceship From Ground is 9 x $10^{10}$