Question

During electrolysis of water the volume of O₂ liberated is 2.24 dm³. The volume of hydrogen liberated, under same conditions will be _______.
(A) 0.56 dm³
(B) 1.12 dm³
(C) 2.24 dm³
(D) 4.48 dm³

Answer 1

Explanation:

option d) 4.48dm is correct answer

Answer 2

Answer:

(D) 4.48 dm³

Explanation:

Liberation of O2 = 2.24 dm³ (Given)

The electrolytic reaction of water has the equation -

2H2O  →→ 2H2 + O2

Therefore, the volume of hydrogen produced will be double the volume as of oxygen.  Hence, the volume of H2 will also be liberated under similar conditions which has released 2.24 dm3 O2 by electrolysis of water.

Volume liberated will be -  

= 2×2.24

= 4.48

The volume of hydrogen liberated, under same conditions will be 4.48 dm³.