The INCORRECT statement for 14 g of CO is _______.
(A) it occupies 2.24 L at NTP
(B) it corresponds to \frac{1}{2} mole of CO
(C) it corresponds to half mole of N₂
(D) it corresponds to 3.01×10²³ molecules of CO
Answers
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Answer:
the answer is option A.
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Answer:
(A) it occupies 2.24 L at NTP
Explanation:
a. The statement is incorrect as 22.4 liters at STP is occupied and not 2.24 L at NTP.
b. This is correct as -
15 × (1 mol /30)
= .5g
c. This is correct as -
Moles of CO = 12 + 16 = 28 g/mol
Moles of N2 = 14 + 14 = 28 g/mol
d. This is also correct as -
= .5 × (6.022 x 10^23 molecules / mol)
= 3.01 x 10^23
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