Question

During the electrolysis of aqueous sodium chloride using Pt-electrodes, the time required to produce 1 mole of H2 gas using a current of 1 amperes is 59.88 h 48.65 h 53.61 h 64.35 h

Answer 1

The time required to liberate 0.01 mole H_2 gas at cathode is: ... Electrolysis of dilute aqueous solution of NaCl was carried out by ... 9.65×104sec ... as reduction potential of sodium ion is lower than that of hydrogen ion so ... The amount of cadium (in gm) that will be deposited by the current flowing for 10 h

Answer 2

Answer:

53.61 hrs ----> option 3

Explanation:

In electrolysis of aq. solution of NaCl,

as reduction potential of sodium ion is lower than that of hydrogen ion so

Cathode :  2H  ⁺  + 2e  −  → H  2

According to faraday's law,

W =  Ei . t  / 96500

0.01×2= (10×10−3 ×t) / 96500   (as E=1 for hydrogen)

t = 19.3×10⁴sec  

∴ t = 53.61 hrs

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