Question

. During upwards and downwards journeys under
gravity, a body passes through a point at 2 s and
14 s. The total height from ground is​

Answer 1

Answer:

let the time taken to reach the top be t. Then,

t=

2

2s+14s

=8s.

Finding initial vel by applying first eqn of motion.

v=u+at

⇒0=4−(10)(8)

⇒u=80 m/s

Finding height by applying third eqn of motion.

v

2

−u

2

=2ah

⇒0−(80)

2

=−2(10)h

⇒h=

20

(80)

2

=320 m. And please please mark me as brainliest....