Question

-e each of the followi
1 to Q. 27)
x2 + 5x+6=0​

Answer 1

${x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 2x + 3x + 6 = 0 \\ x(x + 2) + 3(x + 2) = 0 \\ (x + 2)(x + 3) = 0 \\ x + 2 = 0 \\ x = - 2 \\ \\ x + 3 = 0 \\ x = - 3$

hope it helps

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Answer 2

$\huge\bf\blue {Hey\:Mate!!!}$

Solution :

To find the value of x,we need to factorise the equation on the LHS by splitting the middle term.

${x}^{2} + 5x + 6 = 0 \\ {x}^{2} + 2x + 3x + 6 = 0 \\ x(x + 2) + 3(x + 2) = 0 \\ (x + 2)(x + 3) = 0$

Now here, either (x + 2) or (x + 3) should be equal to 0 so that their multiplication will give product as zero.

$x + 2 = 0 \: or \: x + 3 = 0 \\ x = - 2 \: or \: x = - 3$

@ItsMysteriousGirl✍