Question

E)]
ii) sin t sin 2t sin 3t​

Answer 1

Answer:

sin t sin 2t= 1/2( cos(2t-t) -cos(2t+1))=1/2 ( cos t - cos 3 t)sin 3t

= 1/2 (cos t sin 3t - cos 3 t sin 3t)

1/2 (1/2 (sin 4 t + sin 2t)-1/2 sin 6t)

=1/4 ( sin 4t + sin t - sin 6t)

Now look at the Laplace transforms of sin wt = w/(s^2+w^2)

Use this to write

L transform =1/4( 4/(s^2+16) + 1/(s^2+1) - 6/(s^2+36))

Answer 2

Answer:

Laplace Transform of {sin2t sin3t} is