Question

E is the point on the extended part of the side AD of parallelogram ABCD. and

are intersecting each other at point F. Prove that ∆ABE~∆CFB.

Answer 1

Step-by-step explanation:

In △ABE and △CFB,

∠ABE=∠CFB (Alternate angles)

∠BAE=∠BCF (opposite angles of a parallelogram)

∴ By AA criterion of similarity, △ABE ∼ △CFB