Question

Each digit of a natural number is either 2, 3 or 5 and the number has at least one each of the three digits.
What is the least such number divisible by 18 as well as 12?

Answer 1

Answer:

Answer is 2. because 2 is least number which divisible by 18 and 12.

Answer 2

Answer:

33552

Step-by-step explanation:

No. must be divisible by 36, so it should be divisible by 9 & 4 both...for 4, the last 2 digits must be divisible by 4, it can be either 32 or 52..now sum of the digits should be divisible by 9 ..As the no. must have at least one digit each out of 2,3 and 5 so sum must be greater than 10 so should be 18.

smallest such no. 33552