Each interior angle of a regular polygon is double of its exterior angle .Find the number of sides in the polygon.( WITH PROPER STATEMENTS PLEASE)
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Answered by
32
Let exterior angle be x,
Now each interior angle is 2x, From the data,
We know that interior angle + Exterior angle is always 360°,
Now x + 2x = 360°
=> 3x = 360°,
=> x = 120°, So each interior angle is 120°,
We know that interior angle of a regular polygon is,
Now using that fromula, We need to find n,
=> 180n - 360 = 120n, Since each interior angle is 120°
=> 60n = 360°,
=> n = 6,
Therefore the Polygon is Hexagon which is 6 sided polygon,
Hope you understand, Have a great day !!
Now each interior angle is 2x, From the data,
We know that interior angle + Exterior angle is always 360°,
Now x + 2x = 360°
=> 3x = 360°,
=> x = 120°, So each interior angle is 120°,
We know that interior angle of a regular polygon is,
Now using that fromula, We need to find n,
=> 180n - 360 = 120n, Since each interior angle is 120°
=> 60n = 360°,
=> n = 6,
Therefore the Polygon is Hexagon which is 6 sided polygon,
Hope you understand, Have a great day !!
Bunti360:
Thank you for selecting my answer as Brainliest answer !
Answered by
13
Let Be x
Now x + 2x = 360°
=3x = 360°,
=x = 120°,
So each interior angle is 120°,
180n - 360 = 120n ex a 120°
=60n = 360°
=n = 6
this is right
Now x + 2x = 360°
=3x = 360°,
=x = 120°,
So each interior angle is 120°,
180n - 360 = 120n ex a 120°
=60n = 360°
=n = 6
this is right
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