Math, asked by rajnandanikumar9807, 1 year ago

Each of equal sides of an isosceles triangle is 4 cm greater than 8 height if the base of the triangle is 24 cm calculate the perimeter and the area of a triangle

Answers

Answered by NirajRitesh
2
Peimeter= 4+4+24=32cm
Area= 1/2×b×h
=1/2×24×8
=12×8
=96
Answered by Nivet2006
1

Answer:

Perimeter = 64cm

Area = 192cm^2

Step-by-step explanation:

Base = 24cm

Height = xcm

(x+4)^2 = x^2 + (12)^2

x^2 + 8x + 16 = x^2 + (12)^2

8x = x^2 - x^2 + 144 - 16

8x = 128

x = 128/8

x = 16

Perimeter = 24 + 16+ 4 + 16 + 4

Perimeter = 64cm

Area = \sqrt{s(s-a)(s-b)(s-c)}

{S = 64/2 = 32 ; A = 24 ; B = 20 ; C = 20}

Area = \sqrt{32(32-24)(32-20)(32-20)}

Area = \sqrt{32*8*12*12}

Area = \sqrt{8*4*8*12*12}

Area = 8*2*12

Area = 192cm^{2}

Similar questions