Question

Electric intensity is increased by 3 times the energy density of capacitor

Answer 1

will 8 times of given energy density

Answer 2

Answer: increase by 9 times.

Explanation: As we know, the electric field strength in a capacitor is directly proportional to the applied potential..

And we have been given in this question that the electric intensity becomes 3 times, then the voltage from the first statement will also be 3 times.

So we have V' =3V....... (1)

Now we can find energy density easily by using the formula of energy density;

U= 1/2 CV^2...... (2)

Also

U'= 1/2 CV'^2..... (3)

From equation (1), putting the value of V' in equation (3), we get

U' = 1/2 C ( 3 )^2

U' = 1/2 C ( 9 )

U' = 9 U ( from equation (2) )

Hence the electric density of the capacitor increase by 9 times.