Question

each of the two equal side of an isosceles triangle is three times as large as the third side . if the perimeter of the triangle is 28cm find each side of the triangle

Answer 1

let ABC be the triangle
AB = BC
According to question
AB = BC = 3AC

perimeter of triangle = AB + BC + AC
28 cm = AB + AB + AC
28 cm = 2AB + AC
28 = 2 × 3 AC + AC
28 = 6AC + AC
28 = 7AC
AC = 28/7 = 4cm
AB = BC = 3AC = 3 ×4 = 12cm
Ans. Two sides are 12 cm long and the third side is 4cm long

Answer 2

let the third(smaller)side be x
from the given data we can identify that the two equal sides of the triangle are 3x,
as , perimeter of triangle = sum of it's all sides
28 = 3x + 3x + x
28 = 7x
x = (28/7)
​ x = 4
therefore,
first side- 3x= 3 X 4 = 12cm
second side- 3x= 3 X 4 = 12cm
third side-. x= 4 cm