Question

Each of the two equal sides of an isosceles is twice as large as third side if the perimeter of the triangle is 30 cm find the length of each side of triangle

Answer 1

Let ABC be an isosceles triangle.

therefore, AB = AC

A/Q,

AB=AC= 2BC

Therefore, AB + AC + BC = Perimeter --(1)

=> AB + AC + BC = 30

=> 2BC+2BC+BC =30 (Since AB=AC=2BC)

=> 5BC =30

=> BC=30/5

=> BC= 6

Now, putting the values of AB and AC in equation (1)--

=> AB + AC + BC=30

=> AB + AB + 6 = 30( Since AB=AC)

=> 2AB=30-6

=> AB=24/2=12

Therefore, AB=AC=12, and BC=6

Answer 2

Answer:

Let third side = X

Each of equal sides = 2X

A/q,

X+2X+2X = 30

5X = 30

X = 6

Third side = 6cm

Each of equal sides = 12 cm

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