Each of the two equal sides of an isosceles triangle is 10cmlong then it's area
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Answer: The two of equal sides of an isosceles triangle is 10 cm and the angle between them is 45 degrees. What is the area of the triangle? The area of a triangle is (ab/2)*sin C. Here we have a = b = 10 cm and C = 45 deg, so the area of the isosceles triangle is (10*10/2)sin 45 = 35.35533906 sq cm.
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