Math, asked by kaustubh4354, 10 months ago

Each rectangular tile is 40 cm long and 30 cm wide. How many tiles will be required
to cover the floor of a room with length = 4.8 m and breadth = 2.4 m​

Answers

Answered by aishwaryaauti14
0

the area of a room / the area of a rectangular tile

= 4.8m * 2.4m /40cm * 30cm

= 480cm * 240cm / 40cm * 30cm

= 96

so, 96 tiles are required to cover the floor of a room.

Answered by nandanasubhash123
0

Step-by-step explanation:

Area of tile= L×b

=40×30=1200cm^2

Floor of a room is parallelogram=breadth ×hieght or length

Length=4.8m=4.8×100=480cm

Breadth=2.4×100=240cm

Area=l×b=480×240=115200cm^2

So number of tiles =115200 =96 tiles.

1200

Similar questions