Math, asked by ajbrainly, 7 months ago

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Let A and B be any two sets such that n(B) = p, n(A) = q then the total
number of functions f : A → B is equal to ?
Well, the answer will be q^p. But how? How not pxq?
Somebody please tell me!!!

Answers

Answered by RajatPanwar706
2

Answer:

Given A and B are two sets with number of elements p and q respectively.

The cartesian product of A and B=A×B={(a,b):(a∈A) and (b∈B)}

Number of elements in A×B=∣A×B∣=∣A∣.∣B∣=pq

Any relation from A to B is a subset of A×B.

Hence number of relations from A to B is the number of subsets of A×B

=2

∣A×B∣

=2

pq

Answered by KrishnaKumar01
1

Answer:

 </p><p></p><p> </p><p>\huge{\orange{\overbrace{ \red{ \overbrace{\red{\underbrace \color{blue} {\underbrace \color{black} {\fcolorbox{magenta}{lime}{\fcolorbox{red}{black}{\fcolorbox{pink}{pink}{ \fcolorbox{blue}{blue}{{\bf{{{{\pink{2}}}}}}}}}}}}}}}}}} </p><p>  </p><p>

please mark me as a brainliest

 </p><p></p><p> </p><p>\huge{\orange{\overbrace{ \red{ \overbrace{\red{\underbrace \color{blue} {\underbrace \color{black} {\fcolorbox{magenta}{lime}{\fcolorbox{red}{black}{\fcolorbox{pink}{pink}{ \fcolorbox{blue}{blue}{{\bf{{{{\pink{please \: mark \: me \: as \: a \: brianiliest}}}}}}}}}}}}}}}}}} </p><p>  </p><p>

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