Math, asked by aarjavjan2842, 12 hours ago

Eight members A, B, C, D, E, F, G and H belonging to three families X, Y, Z go for weekend outing in three different cars I, II, III. Four out of eight members are females. Members of eachfamily travel in different cars. Each car has at least one male and one female. Each family has at least two members.A belong to family Y and he travels in car III. D is wife of E and they travel in cars I and II respectively. His son of B who is wife of G and they belong to family Z. Cis daughter of F who is wíof A. C travels in car II. G does not travel with F.Which of the following combination of family members belongs to same family?​

Answers

Answered by vv5320
1

Answer:

A B C D E F G H I J K L M N O P Q R ST U V W X Y Z

Answered by kingofself
0

Answer:

Family x = D E

Family Y = A F  C

Family Z = G B H

Step-by-step explanation:

FAMILY X = D(Female) is wife and E(Male) is Husband.

FAMILY Y = F(Female) is wife and A(Male) is Husband and C(Female) is a daughter

FAMILY Z = B(Female) is wife and G(Male) is Husband. and H(male) is a son.

GIVEN CONDITIONS:

C travels in car II.

A belong to family Y and he travels in car II

D is wife of E and they travel in cars I and II respectively.

From above conditions      

CAR I     D  

CAR II    E A

CAR III   C

Indirect Conditions:

Four out of eight members are females

Members of each family travel in different cars.

Each car has at least one male and one female.

G does not travel with F

CAR I     D F H

CAR II    E A B

CAR III   C G

*Bold letters are females

*italic letters are family x

*underlined letters are family y

* normal letters are family z.

All conditions are satisfied.

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